Base | Representation |
---|---|
bin | 111010100000001001110… |
… | …001101010111101001011 |
3 | 112020022222101001021111101 |
4 | 322200021301222331023 |
5 | 1011331434332430003 |
6 | 12314513502442231 |
7 | 563311425053113 |
oct | 72401161527513 |
9 | 15208871037441 |
10 | 4020253405003 |
11 | 130aa8626a610 |
12 | 54b19a893377 |
13 | 232153b38854 |
14 | dc81d14a043 |
15 | 6e8990ce11d |
hex | 3a809c6af4b |
4020253405003 has 32 divisors (see below), whose sum is σ = 4456679657472. Its totient is φ = 3596184026400.
The previous prime is 4020253404971. The next prime is 4020253405031. The reversal of 4020253405003 is 3005043520204.
4020253405003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 4020253405003 - 25 = 4020253404971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4020253405303) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 124902450 + ... + 124934632.
It is an arithmetic number, because the mean of its divisors is an integer number (139271239296).
Almost surely, 24020253405003 is an apocalyptic number.
4020253405003 is a deficient number, since it is larger than the sum of its proper divisors (436426252469).
4020253405003 is a wasteful number, since it uses less digits than its factorization.
4020253405003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33015.
The product of its (nonzero) digits is 14400, while the sum is 28.
Adding to 4020253405003 its reverse (3005043520204), we get a palindrome (7025296925207).
The spelling of 4020253405003 in words is "four trillion, twenty billion, two hundred fifty-three million, four hundred five thousand, three".
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