40205315234013 has 4 divisors (see below), whose sum is σ = 53607086978688. Its totient is φ = 26803543489340.

The previous prime is 40205315233991. The next prime is 40205315234083. The reversal of 40205315234013 is 31043251350204.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40205315234013 - 2⁵ = 40205315233981 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40205315234083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6700885872333 + ... + 6700885872338.

It is an arithmetic number, because the mean of its divisors is an integer number (13401771744672).

Almost surely, 2^{40205315234013} is an apocalyptic number.

It is an amenable number.

40205315234013 is a deficient number, since it is larger than the sum of its proper divisors (13401771744675).

40205315234013 is a wasteful number, since it uses less digits than its factorization.

40205315234013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13401771744674.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 40205315234013 its reverse (31043251350204), we get a palindrome (71248566584217).

The spelling of 40205315234013 in words is "forty trillion, two hundred five billion, three hundred fifteen million, two hundred thirty-four thousand, thirteen".