Base | Representation |
---|---|
bin | 1011101100111000101… |
… | …11000010100101100101 |
3 | 1102102202220212120220220 |
4 | 11312130113002211211 |
5 | 23041402120303013 |
6 | 504411315114553 |
7 | 41022206121264 |
oct | 5663427024545 |
9 | 1372686776826 |
10 | 402055244133 |
11 | 145568781774 |
12 | 65b075a2a59 |
13 | 2bbb5388a2a |
14 | 1566111c5db |
15 | a6d206eb23 |
hex | 5d9c5c2965 |
402055244133 has 4 divisors (see below), whose sum is σ = 536073658848. Its totient is φ = 268036829420.
The previous prime is 402055244111. The next prime is 402055244189. The reversal of 402055244133 is 331442550204.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 402055244133 - 230 = 400981502309 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 402055244094 and 402055244103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (402055244233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67009207353 + ... + 67009207358.
It is an arithmetic number, because the mean of its divisors is an integer number (134018414712).
Almost surely, 2402055244133 is an apocalyptic number.
It is an amenable number.
402055244133 is a deficient number, since it is larger than the sum of its proper divisors (134018414715).
402055244133 is a wasteful number, since it uses less digits than its factorization.
402055244133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 134018414714.
The product of its (nonzero) digits is 57600, while the sum is 33.
Adding to 402055244133 its reverse (331442550204), we get a palindrome (733497794337).
The spelling of 402055244133 in words is "four hundred two billion, fifty-five million, two hundred forty-four thousand, one hundred thirty-three".
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