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4021314013004 = 221005328503251
BaseRepresentation
bin111010100001001000111…
…111100100011101001100
3112020102201021202202011012
4322201020333210131030
51011341122341404004
612315211031144352
7563346624062531
oct72411077443514
915212637682135
104021314013004
11131047aa1a052
1254b435b150b8
132322927a6652
14dc8bdd52d88
156e90c28346e
hex3a848fe474c

4021314013004 has 6 divisors (see below), whose sum is σ = 7037299522764. Its totient is φ = 2010657006500.

The previous prime is 4021314012977. The next prime is 4021314013027. The reversal of 4021314013004 is 4003104131204.

4021314013004 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×40213140130042 (a number of 26 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502664251622 + ... + 502664251629.

It is an arithmetic number, because the mean of its divisors is an integer number (1172883253794).

Almost surely, 24021314013004 is an apocalyptic number.

It is an amenable number.

4021314013004 is a deficient number, since it is larger than the sum of its proper divisors (3015985509760).

4021314013004 is a wasteful number, since it uses less digits than its factorization.

4021314013004 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1005328503255 (or 1005328503253 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 4021314013004 its reverse (4003104131204), we get a palindrome (8024418144208).

The spelling of 4021314013004 in words is "four trillion, twenty-one billion, three hundred fourteen million, thirteen thousand, four".

Divisors: 1 2 4 1005328503251 2010657006502 4021314013004