Base | Representation |
---|---|
bin | 111010100001001000111… |
… | …111100100011101001100 |
3 | 112020102201021202202011012 |
4 | 322201020333210131030 |
5 | 1011341122341404004 |
6 | 12315211031144352 |
7 | 563346624062531 |
oct | 72411077443514 |
9 | 15212637682135 |
10 | 4021314013004 |
11 | 131047aa1a052 |
12 | 54b435b150b8 |
13 | 2322927a6652 |
14 | dc8bdd52d88 |
15 | 6e90c28346e |
hex | 3a848fe474c |
4021314013004 has 6 divisors (see below), whose sum is σ = 7037299522764. Its totient is φ = 2010657006500.
The previous prime is 4021314012977. The next prime is 4021314013027. The reversal of 4021314013004 is 4003104131204.
4021314013004 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×40213140130042 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502664251622 + ... + 502664251629.
It is an arithmetic number, because the mean of its divisors is an integer number (1172883253794).
Almost surely, 24021314013004 is an apocalyptic number.
It is an amenable number.
4021314013004 is a deficient number, since it is larger than the sum of its proper divisors (3015985509760).
4021314013004 is a wasteful number, since it uses less digits than its factorization.
4021314013004 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1005328503255 (or 1005328503253 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 4021314013004 its reverse (4003104131204), we get a palindrome (8024418144208).
The spelling of 4021314013004 in words is "four trillion, twenty-one billion, three hundred fourteen million, thirteen thousand, four".
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