4021441412031 has 12 divisors (see below), whose sum is σ = 5812813629480. Its totient is φ = 2679084822960.

The previous prime is 4021441411997. The next prime is 4021441412041. The reversal of 4021441412031 is 1302141441204.

4021441412031 is a `hidden beast` number, since 4 + 0 + 214 + 4 + 1 + 412 + 0 + 31 = 666.

It is not a de Polignac number, because 4021441412031 - 2¹¹ = 4021441409983 is a prime.

It is a super-3 number, since 3×4021441412031³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 4021441411986 and 4021441412004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4021441412041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 156329625 + ... + 156355346.

It is an arithmetic number, because the mean of its divisors is an integer number (484401135790).

Almost surely, 2^{4021441412031} is an apocalyptic number.

4021441412031 is a deficient number, since it is larger than the sum of its proper divisors (1791372217449).

4021441412031 is a wasteful number, since it uses less digits than its factorization.

4021441412031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 312686406 (or 312686403 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 27.

Adding to 4021441412031 its reverse (1302141441204), we get a palindrome (5323582853235).

The spelling of 4021441412031 in words is "four trillion, twenty-one billion, four hundred forty-one million, four hundred twelve thousand, thirty-one".