4022040314113 has 4 divisors (see below), whose sum is σ = 4037333243328. Its totient is φ = 4006747384900.

The previous prime is 4022040314081. The next prime is 4022040314143. The reversal of 4022040314113 is 3114130402204.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4022040314113 - 2⁵ = 4022040314081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4022040314143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7646464213 + ... + 7646464738.

It is an arithmetic number, because the mean of its divisors is an integer number (1009333310832).

Almost surely, 2^{4022040314113} is an apocalyptic number.

It is an amenable number.

4022040314113 is a deficient number, since it is larger than the sum of its proper divisors (15292929215).

4022040314113 is a wasteful number, since it uses less digits than its factorization.

4022040314113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15292929214.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 4022040314113 its reverse (3114130402204), we get a palindrome (7136170716317).

The spelling of 4022040314113 in words is "four trillion, twenty-two billion, forty million, three hundred fourteen thousand, one hundred thirteen".