Base | Representation |
---|---|
bin | 10010010010111001000000… |
… | …10001101000001000000001 |
3 | 12021110002112102022021201000 |
4 | 21021130200101220020001 |
5 | 20233123103014401340 |
6 | 221322032424002213 |
7 | 11321426035633344 |
oct | 1111344021501001 |
9 | 167402472267630 |
10 | 40231500153345 |
11 | 119010a1004756 |
12 | 4619174000369 |
13 | 195aa779c5a17 |
14 | 9d1301d4845b |
15 | 49b7a8844d30 |
hex | 249720468201 |
40231500153345 has 32 divisors (see below), whose sum is σ = 71522943408000. Its totient is φ = 21456717141312.
The previous prime is 40231500153331. The next prime is 40231500153421. The reversal of 40231500153345 is 54335100513204.
40231500153345 is a `hidden beast` number, since 4 + 0 + 2 + 31 + 50 + 0 + 1 + 533 + 45 = 666.
It is not a de Polignac number, because 40231500153345 - 221 = 40231498056193 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 52580539 + ... + 53340191.
It is an arithmetic number, because the mean of its divisors is an integer number (2235091981500).
Almost surely, 240231500153345 is an apocalyptic number.
40231500153345 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
It is an amenable number.
40231500153345 is a deficient number, since it is larger than the sum of its proper divisors (31291443254655).
40231500153345 is a wasteful number, since it uses less digits than its factorization.
40231500153345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1151966 (or 1151960 counting only the distinct ones).
The product of its (nonzero) digits is 108000, while the sum is 36.
Adding to 40231500153345 its reverse (54335100513204), we get a palindrome (94566600666549).
The spelling of 40231500153345 in words is "forty trillion, two hundred thirty-one billion, five hundred million, one hundred fifty-three thousand, three hundred forty-five".
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