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4023234421341 = 319717413910111
BaseRepresentation
bin111010100010111011011…
…101010110001001011101
3112020121200010100121010220
4322202323131112021131
51011404041002440331
612320125352151553
7563445333221622
oct72427335261135
915217603317126
104023234421341
111311275a44283
1254b8910985b9
1323250a604445
14dca23010349
156e9c0b73296
hex3a8bb75625d

4023234421341 has 16 divisors (see below), whose sum is σ = 5394640762368. Its totient is φ = 2667007828800.

The previous prime is 4023234421309. The next prime is 4023234421357. The reversal of 4023234421341 is 1431244323204.

It is not a de Polignac number, because 4023234421341 - 25 = 4023234421309 is a prime.

It is a super-2 number, since 2×40232344213412 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4023234421541) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 926125 + ... + 2983986.

It is an arithmetic number, because the mean of its divisors is an integer number (337165047648).

Almost surely, 24023234421341 is an apocalyptic number.

It is an amenable number.

4023234421341 is a deficient number, since it is larger than the sum of its proper divisors (1371406341027).

4023234421341 is a wasteful number, since it uses less digits than its factorization.

4023234421341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3912052.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 4023234421341 its reverse (1431244323204), we get a palindrome (5454478744545).

The spelling of 4023234421341 in words is "four trillion, twenty-three billion, two hundred thirty-four million, four hundred twenty-one thousand, three hundred forty-one".

Divisors: 1 3 197 591 1741 5223 342977 1028931 3910111 11730333 770291867 2310875601 6807503251 20422509753 1341078140447 4023234421341