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40240113 = 313413371
BaseRepresentation
bin1001100110000…
…0001111110001
32210201102001120
42121200033301
540300140423
63554252453
7666015054
oct231401761
983642046
1040240113
1120794aa1
1211587129
13844bc24
1454b6a9b
1537ecee3
hex26603f1

40240113 has 4 divisors (see below), whose sum is σ = 53653488. Its totient is φ = 26826740.

The previous prime is 40240093. The next prime is 40240129. The reversal of 40240113 is 31104204.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40240113 - 212 = 40236017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 40240092 and 40240101.

It is not an unprimeable number, because it can be changed into a prime (40240163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6706683 + ... + 6706688.

It is an arithmetic number, because the mean of its divisors is an integer number (13413372).

Almost surely, 240240113 is an apocalyptic number.

It is an amenable number.

40240113 is a deficient number, since it is larger than the sum of its proper divisors (13413375).

40240113 is a wasteful number, since it uses less digits than its factorization.

40240113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13413374.

The product of its (nonzero) digits is 96, while the sum is 15.

The square root of 40240113 is about 6343.5095176093. The cubic root of 40240113 is about 342.6781370384.

Adding to 40240113 its reverse (31104204), we get a palindrome (71344317).

The spelling of 40240113 in words is "forty million, two hundred forty thousand, one hundred thirteen".

Divisors: 1 3 13413371 40240113