40241114241133 has 4 divisors (see below), whose sum is σ = 43336584567388. Its totient is φ = 37145643914880.

The previous prime is 40241114241043. The next prime is 40241114241149. The reversal of 40241114241133 is 33114241114204.

40241114241133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 18904077885924 + 21337036355209 = 4347882^2 + 4619203^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-40241114241133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 40241114241095 and 40241114241104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40241114245133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1547735163108 + ... + 1547735163133.

It is an arithmetic number, because the mean of its divisors is an integer number (10834146141847).

Almost surely, 2^{40241114241133} is an apocalyptic number.

It is an amenable number.

40241114241133 is a deficient number, since it is larger than the sum of its proper divisors (3095470326255).

40241114241133 is a wasteful number, since it uses less digits than its factorization.

40241114241133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3095470326254.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 40241114241133 its reverse (33114241114204), we get a palindrome (73355355355337).

The spelling of 40241114241133 in words is "forty trillion, two hundred forty-one billion, one hundred fourteen million, two hundred forty-one thousand, one hundred thirty-three".