40241131440131 has 4 divisors (see below), whose sum is σ = 40241227937232. Its totient is φ = 40241034943032.

The previous prime is 40241131440121. The next prime is 40241131440157. The reversal of 40241131440131 is 13104413114204.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40241131440131 - 2¹⁴ = 40241131423747 is a prime.

It is a super-2 number, since 2×40241131440131² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 40241131440094 and 40241131440103.

It is not an unprimeable number, because it can be changed into a prime (40241131440101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47620295 + ... + 48457968.

It is an arithmetic number, because the mean of its divisors is an integer number (10060306984308).

Almost surely, 2^{40241131440131} is an apocalyptic number.

40241131440131 is a deficient number, since it is larger than the sum of its proper divisors (96497101).

40241131440131 is an equidigital number, since it uses as much as digits as its factorization.

40241131440131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 96497100.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 40241131440131 its reverse (13104413114204), we get a palindrome (53345544554335).

The spelling of 40241131440131 in words is "forty trillion, two hundred forty-one billion, one hundred thirty-one million, four hundred forty thousand, one hundred thirty-one".