40241215352533 has 4 divisors (see below), whose sum is σ = 43336693456588. Its totient is φ = 37145737248480.

The previous prime is 40241215352461. The next prime is 40241215352537. The reversal of 40241215352533 is 33525351214204.

40241215352533 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 23690044686564 + 16551170665969 = 4867242^2 + 4068313^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-40241215352533 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40241215352537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1547739052008 + ... + 1547739052033.

It is an arithmetic number, because the mean of its divisors is an integer number (10834173364147).

Almost surely, 2^{40241215352533} is an apocalyptic number.

It is an amenable number.

40241215352533 is a deficient number, since it is larger than the sum of its proper divisors (3095478104055).

40241215352533 is a wasteful number, since it uses less digits than its factorization.

40241215352533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3095478104054.

The product of its (nonzero) digits is 432000, while the sum is 40.

Adding to 40241215352533 its reverse (33525351214204), we get a palindrome (73766566566737).

The spelling of 40241215352533 in words is "forty trillion, two hundred forty-one billion, two hundred fifteen million, three hundred fifty-two thousand, five hundred thirty-three".