Base | Representation |
---|---|
bin | 10010010011010010101110… |
… | …00000111010101000001011 |
3 | 12021111102011101120221212002 |
4 | 21021221113000322220023 |
5 | 20233334340133441301 |
6 | 221332234231541215 |
7 | 11322425064525452 |
oct | 1111512700725013 |
9 | 167442141527762 |
10 | 40245303421451 |
11 | 11906a34652347 |
12 | 461b98682a80b |
13 | 195c167622c9b |
14 | 9d1c5124db99 |
15 | 49bd1556716b |
hex | 249a5703aa0b |
40245303421451 has 4 divisors (see below), whose sum is σ = 40245487811304. Its totient is φ = 40245119031600.
The previous prime is 40245303421343. The next prime is 40245303421489. The reversal of 40245303421451 is 15412430354204.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 40245303421451 - 218 = 40245303159307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (40245303421651) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91867145 + ... + 92304186.
It is an arithmetic number, because the mean of its divisors is an integer number (10061371952826).
Almost surely, 240245303421451 is an apocalyptic number.
40245303421451 is a deficient number, since it is larger than the sum of its proper divisors (184389853).
40245303421451 is a wasteful number, since it uses less digits than its factorization.
40245303421451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 184389852.
The product of its (nonzero) digits is 230400, while the sum is 38.
Adding to 40245303421451 its reverse (15412430354204), we get a palindrome (55657733775655).
The spelling of 40245303421451 in words is "forty trillion, two hundred forty-five billion, three hundred three million, four hundred twenty-one thousand, four hundred fifty-one".
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