40250551133031 has 4 divisors (see below), whose sum is σ = 53667401510712. Its totient is φ = 26833700755352.

The previous prime is 40250551132997. The next prime is 40250551133033. The reversal of 40250551133031 is 13033115505204.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40250551133031 - 2⁷ = 40250551132903 is a prime.

It is a super-2 number, since 2×40250551133031² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40250551132983 and 40250551133001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40250551133033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6708425188836 + ... + 6708425188841.

It is an arithmetic number, because the mean of its divisors is an integer number (13416850377678).

Almost surely, 2^{40250551133031} is an apocalyptic number.

40250551133031 is a deficient number, since it is larger than the sum of its proper divisors (13416850377681).

40250551133031 is a wasteful number, since it uses less digits than its factorization.

40250551133031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13416850377680.

The product of its (nonzero) digits is 27000, while the sum is 33.

Adding to 40250551133031 its reverse (13033115505204), we get a palindrome (53283666638235).

The spelling of 40250551133031 in words is "forty trillion, two hundred fifty billion, five hundred fifty-one million, one hundred thirty-three thousand, thirty-one".