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40253054713 = 192118581827
BaseRepresentation
bin100101011111010001…
…001101111011111001
310211220022020001022021
4211133101031323321
51124414240222323
630254134354441
72623336214434
oct453721157371
9124808201267
1040253054713
1116086888873
1279747bba21
133a46624491
141d3c04081b
1510a8d2105d
hex95f44def9

40253054713 has 4 divisors (see below), whose sum is σ = 42371636560. Its totient is φ = 38134472868.

The previous prime is 40253054707. The next prime is 40253054761. The reversal of 40253054713 is 31745035204.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40253054713 - 213 = 40253046521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (40253054773) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1059290895 + ... + 1059290932.

It is an arithmetic number, because the mean of its divisors is an integer number (10592909140).

Almost surely, 240253054713 is an apocalyptic number.

It is an amenable number.

40253054713 is a deficient number, since it is larger than the sum of its proper divisors (2118581847).

40253054713 is a wasteful number, since it uses less digits than its factorization.

40253054713 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2118581846.

The product of its (nonzero) digits is 50400, while the sum is 34.

Adding to 40253054713 its reverse (31745035204), we get a palindrome (71998089917).

The spelling of 40253054713 in words is "forty billion, two hundred fifty-three million, fifty-four thousand, seven hundred thirteen".

Divisors: 1 19 2118581827 40253054713