40302013404343 has 4 divisors (see below), whose sum is σ = 40351102337448. Its totient is φ = 40252924471240.

The previous prime is 40302013404319. The next prime is 40302013404371. The reversal of 40302013404343 is 34340431020304.

40302013404343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40302013404343 - 2¹⁷ = 40302013273271 is a prime.

It is a super-3 number, since 3×40302013404343³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40302013404743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24544465321 + ... + 24544466962.

It is an arithmetic number, because the mean of its divisors is an integer number (10087775584362).

Almost surely, 2^{40302013404343} is an apocalyptic number.

40302013404343 is a deficient number, since it is larger than the sum of its proper divisors (49088933105).

40302013404343 is an equidigital number, since it uses as much as digits as its factorization.

40302013404343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49088933104.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 40302013404343 its reverse (34340431020304), we get a palindrome (74642444424647).

The spelling of 40302013404343 in words is "forty trillion, three hundred two billion, thirteen million, four hundred four thousand, three hundred forty-three".