Base | Representation |
---|---|
bin | 111010101010010111000… |
… | …010011001010011100011 |
3 | 112021101021012001012101020 |
4 | 322222113002121103203 |
5 | 1012021411101424303 |
6 | 12323525215340523 |
7 | 564150136530321 |
oct | 72522702312343 |
9 | 15241235035336 |
10 | 4031213311203 |
11 | 131469a903331 |
12 | 551339221743 |
13 | 2331ac665a50 |
14 | dd17c980d11 |
15 | 6ecdb39da53 |
hex | 3aa970994e3 |
4031213311203 has 16 divisors (see below), whose sum is σ = 5929589563296. Its totient is φ = 2420240636160.
The previous prime is 4031213311193. The next prime is 4031213311253. The reversal of 4031213311203 is 3021133121304.
4031213311203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4031213311203 - 229 = 4030676440291 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4031213311253) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1260540400 + ... + 1260543597.
It is an arithmetic number, because the mean of its divisors is an integer number (370599347706).
Almost surely, 24031213311203 is an apocalyptic number.
4031213311203 is a deficient number, since it is larger than the sum of its proper divisors (1898376252093).
4031213311203 is a wasteful number, since it uses less digits than its factorization.
4031213311203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2521084054.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 4031213311203 its reverse (3021133121304), we get a palindrome (7052346432507).
The spelling of 4031213311203 in words is "four trillion, thirty-one billion, two hundred thirteen million, three hundred eleven thousand, two hundred three".
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