Base | Representation |
---|---|
bin | 111010101010011100111… |
… | …111001011001010010111 |
3 | 112021101112010212112012201 |
4 | 322222130333023022113 |
5 | 1012022112130131020 |
6 | 12323543143025331 |
7 | 564152461136524 |
oct | 72523477131227 |
9 | 15241463775181 |
10 | 4031313130135 |
11 | 1314741190815 |
12 | 55136673b247 |
13 | 2331c7244cc5 |
14 | dd18bd2614b |
15 | 6ece5019a0a |
hex | 3aa9cfcb297 |
4031313130135 has 4 divisors (see below), whose sum is σ = 4837575756168. Its totient is φ = 3225050504104.
The previous prime is 4031313130093. The next prime is 4031313130181. The reversal of 4031313130135 is 5310313131304.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4031313130135 - 219 = 4031312605847 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 403131313009 + ... + 403131313018.
It is an arithmetic number, because the mean of its divisors is an integer number (1209393939042).
Almost surely, 24031313130135 is an apocalyptic number.
4031313130135 is a deficient number, since it is larger than the sum of its proper divisors (806262626033).
4031313130135 is an equidigital number, since it uses as much as digits as its factorization.
4031313130135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 806262626032.
The product of its (nonzero) digits is 4860, while the sum is 28.
Adding to 4031313130135 its reverse (5310313131304), we get a palindrome (9341626261439).
The spelling of 4031313130135 in words is "four trillion, thirty-one billion, three hundred thirteen million, one hundred thirty thousand, one hundred thirty-five".
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