Base | Representation |
---|---|
bin | 111010101010011101101… |
… | …001100001011001001011 |
3 | 112021101112220202112001212 |
4 | 322222131221201121023 |
5 | 1012022123000344433 |
6 | 12323544221003335 |
7 | 564152654403341 |
oct | 72523551413113 |
9 | 15241486675055 |
10 | 4031324231243 |
11 | 1314747483191 |
12 | 55136a3b354b |
13 | 2331c9630aca |
14 | dd18d5b5991 |
15 | 6ece5eadd48 |
hex | 3aa9da6164b |
4031324231243 has 4 divisors (see below), whose sum is σ = 4031361780048. Its totient is φ = 4031286682440.
The previous prime is 4031324231239. The next prime is 4031324231257. The reversal of 4031324231243 is 3421324231304.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4031324231243 - 22 = 4031324231239 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4031324261243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18612896 + ... + 18828237.
It is an arithmetic number, because the mean of its divisors is an integer number (1007840445012).
Almost surely, 24031324231243 is an apocalyptic number.
4031324231243 is a deficient number, since it is larger than the sum of its proper divisors (37548805).
4031324231243 is a wasteful number, since it uses less digits than its factorization.
4031324231243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37548804.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 4031324231243 its reverse (3421324231304), we get a palindrome (7452648462547).
The spelling of 4031324231243 in words is "four trillion, thirty-one billion, three hundred twenty-four million, two hundred thirty-one thousand, two hundred forty-three".
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