Base | Representation |
---|---|
bin | 10010010101010100110010… |
… | …10001010110011000000001 |
3 | 12021202002102001002102100120 |
4 | 21022222121101112120001 |
5 | 20241010343413034101 |
6 | 221424303410210453 |
7 | 11330446421110653 |
oct | 1112523121263001 |
9 | 167662361072316 |
10 | 40315134502401 |
11 | 1193360945aaa0 |
12 | 4631414b83a29 |
13 | 1965915a76325 |
14 | 9d53976546d3 |
15 | 49da50e0cb36 |
hex | 24aa99456601 |
40315134502401 has 64 divisors (see below), whose sum is σ = 61374893045760. Its totient is φ = 23300456960000.
The previous prime is 40315134502387. The next prime is 40315134502429. The reversal of 40315134502401 is 10420543151304.
It is not a de Polignac number, because 40315134502401 - 25 = 40315134502369 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is not an unprimeable number, because it can be changed into a prime (40315134502451) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 509112031 + ... + 509191211.
It is an arithmetic number, because the mean of its divisors is an integer number (958982703840).
Almost surely, 240315134502401 is an apocalyptic number.
It is an amenable number.
40315134502401 is a deficient number, since it is larger than the sum of its proper divisors (21059758543359).
40315134502401 is a wasteful number, since it uses less digits than its factorization.
40315134502401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81238.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 40315134502401 its reverse (10420543151304), we get a palindrome (50735677653705).
The spelling of 40315134502401 in words is "forty trillion, three hundred fifteen billion, one hundred thirty-four million, five hundred two thousand, four hundred one".
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