Base | Representation |
---|---|
bin | 100101100010111110… |
… | …101101110011000001 |
3 | 10212001122101010002112 |
4 | 211202332231303001 |
5 | 1130031210011340 |
6 | 30304241025105 |
7 | 2625023336456 |
oct | 454276556301 |
9 | 125048333075 |
10 | 40315313345 |
11 | 16108a4168a |
12 | 7991625195 |
13 | 3a564b24c8 |
14 | 1d4640982d |
15 | 10ae51d065 |
hex | 962fadcc1 |
40315313345 has 4 divisors (see below), whose sum is σ = 48378376020. Its totient is φ = 32252250672.
The previous prime is 40315313333. The next prime is 40315313347. The reversal of 40315313345 is 54331351304.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 21104244529 + 19211068816 = 145273^2 + 138604^2 .
It is a cyclic number.
It is not a de Polignac number, because 40315313345 - 222 = 40311119041 is a prime.
It is not an unprimeable number, because it can be changed into a prime (40315313347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4031531330 + ... + 4031531339.
It is an arithmetic number, because the mean of its divisors is an integer number (12094594005).
Almost surely, 240315313345 is an apocalyptic number.
It is an amenable number.
40315313345 is a deficient number, since it is larger than the sum of its proper divisors (8063062675).
40315313345 is an equidigital number, since it uses as much as digits as its factorization.
40315313345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8063062674.
The product of its (nonzero) digits is 32400, while the sum is 32.
Adding to 40315313345 its reverse (54331351304), we get a palindrome (94646664649).
The spelling of 40315313345 in words is "forty billion, three hundred fifteen million, three hundred thirteen thousand, three hundred forty-five".
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