Base | Representation |
---|---|
bin | 10010010101110010110000… |
… | …10011100100000111100001 |
3 | 12021210121221101010120220120 |
4 | 21022321120103210013201 |
5 | 20241241321423324441 |
6 | 221435524141230453 |
7 | 11331556224214656 |
oct | 1112713023440741 |
9 | 167717841116816 |
10 | 40331224433121 |
11 | 1193a41583a0a6 |
12 | 4634565562429 |
13 | 19672ab358aab |
14 | 9d6082515c2d |
15 | 49e193769966 |
hex | 24ae584e41e1 |
40331224433121 has 32 divisors (see below), whose sum is σ = 54680307793920. Its totient is φ = 26436936052800.
The previous prime is 40331224433107. The next prime is 40331224433161. The reversal of 40331224433121 is 12133442213304.
It is not a de Polignac number, because 40331224433121 - 210 = 40331224432097 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (40331224433161) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 164447016 + ... + 164692086.
It is an arithmetic number, because the mean of its divisors is an integer number (1708759618560).
Almost surely, 240331224433121 is an apocalyptic number.
It is an amenable number.
40331224433121 is a deficient number, since it is larger than the sum of its proper divisors (14349083360799).
40331224433121 is a wasteful number, since it uses less digits than its factorization.
40331224433121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 247237.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 40331224433121 its reverse (12133442213304), we get a palindrome (52464666646425).
The spelling of 40331224433121 in words is "forty trillion, three hundred thirty-one billion, two hundred twenty-four million, four hundred thirty-three thousand, one hundred twenty-one".
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