Base | Representation |
---|---|
bin | 10010010101110010111101… |
… | …01011011000100001111011 |
3 | 12021210122012211022001010211 |
4 | 21022321132223120201323 |
5 | 20241242031310343121 |
6 | 221435542520451551 |
7 | 11331561663006016 |
oct | 1112713653304173 |
9 | 167718184261124 |
10 | 40331331340411 |
11 | 1193a470119131 |
12 | 4634595319bb7 |
13 | 19672c754a547 |
14 | 9d60927c437d |
15 | 49e19cd35ce1 |
hex | 24ae5ead887b |
40331331340411 has 4 divisors (see below), whose sum is σ = 40336904282752. Its totient is φ = 40325758398072.
The previous prime is 40331331340387. The next prime is 40331331340429. The reversal of 40331331340411 is 11404313313304.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 40331331340411 - 27 = 40331331340283 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (40331331340441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2786460315 + ... + 2786474788.
It is an arithmetic number, because the mean of its divisors is an integer number (10084226070688).
Almost surely, 240331331340411 is an apocalyptic number.
40331331340411 is a deficient number, since it is larger than the sum of its proper divisors (5572942341).
40331331340411 is an equidigital number, since it uses as much as digits as its factorization.
40331331340411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5572942340.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 40331331340411 its reverse (11404313313304), we get a palindrome (51735644653715).
The spelling of 40331331340411 in words is "forty trillion, three hundred thirty-one billion, three hundred thirty-one million, three hundred forty thousand, four hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •