Base | Representation |
---|---|
bin | 100101100100011101… |
… | …010010000100001001 |
3 | 10212010101000120200221 |
4 | 211210131102010021 |
5 | 1130104031302213 |
6 | 30310524230041 |
7 | 2625444136000 |
oct | 454435220411 |
9 | 125111016627 |
10 | 40340103433 |
11 | 16120a33863 |
12 | 799999b321 |
13 | 3a5b681cb6 |
14 | 1d4981dc37 |
15 | 10b17b838d |
hex | 964752109 |
40340103433 has 16 divisors (see below), whose sum is σ = 47105020800. Its totient is φ = 34532273328.
The previous prime is 40340103413. The next prime is 40340103457. The reversal of 40340103433 is 33430104304.
It is not a de Polignac number, because 40340103433 - 29 = 40340102921 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 40340103398 and 40340103407.
It is not an unprimeable number, because it can be changed into a prime (40340103413) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 189066 + ... + 341212.
It is an arithmetic number, because the mean of its divisors is an integer number (2944063800).
Almost surely, 240340103433 is an apocalyptic number.
It is an amenable number.
40340103433 is a deficient number, since it is larger than the sum of its proper divisors (6764917367).
40340103433 is an equidigital number, since it uses as much as digits as its factorization.
40340103433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 152941 (or 152927 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 40340103433 its reverse (33430104304), we get a palindrome (73770207737).
The spelling of 40340103433 in words is "forty billion, three hundred forty million, one hundred three thousand, four hundred thirty-three".
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