Base | Representation |
---|---|
bin | 10010010110000011010100… |
… | …00001001100111100110011 |
3 | 12021211110212201210121022121 |
4 | 21023001222001030330303 |
5 | 20241413022023402430 |
6 | 221443554051015111 |
7 | 11332322366342365 |
oct | 1113015201147463 |
9 | 167743781717277 |
10 | 40340111544115 |
11 | 11943166336129 |
12 | 463622589a497 |
13 | 1968096601a56 |
14 | 9d6686942d35 |
15 | 49e513a97a7a |
hex | 24b06a04cf33 |
40340111544115 has 4 divisors (see below), whose sum is σ = 48408133852944. Its totient is φ = 32272089235288.
The previous prime is 40340111544077. The next prime is 40340111544163. The reversal of 40340111544115 is 51144511104304.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 40340111544115 - 215 = 40340111511347 is a prime.
It is a super-2 number, since 2×403401115441152 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4034011154407 + ... + 4034011154416.
It is an arithmetic number, because the mean of its divisors is an integer number (12102033463236).
Almost surely, 240340111544115 is an apocalyptic number.
40340111544115 is a deficient number, since it is larger than the sum of its proper divisors (8068022308829).
40340111544115 is an equidigital number, since it uses as much as digits as its factorization.
40340111544115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8068022308828.
The product of its (nonzero) digits is 19200, while the sum is 34.
Adding to 40340111544115 its reverse (51144511104304), we get a palindrome (91484622648419).
The spelling of 40340111544115 in words is "forty trillion, three hundred forty billion, one hundred eleven million, five hundred forty-four thousand, one hundred fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •