Base | Representation |
---|---|
bin | 111010101101000110010… |
… | …001100100100110001101 |
3 | 112021122212002011020010120 |
4 | 322231012101210212031 |
5 | 1012043421221134123 |
6 | 12325133041455153 |
7 | 564313036201263 |
oct | 72550621444615 |
9 | 15248762136116 |
10 | 4034153302413 |
11 | 1315969407233 |
12 | 551a199414b9 |
13 | 23355a799310 |
14 | dd37b206433 |
15 | 6ee0e53c2e3 |
hex | 3ab4646498d |
4034153302413 has 16 divisors (see below), whose sum is σ = 5801667283776. Its totient is φ = 2478682920960.
The previous prime is 4034153302409. The next prime is 4034153302441. The reversal of 4034153302413 is 3142033514304.
4034153302413 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4034153302413 - 22 = 4034153302409 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4034153302453) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 80661295 + ... + 80711292.
It is an arithmetic number, because the mean of its divisors is an integer number (362604205236).
Almost surely, 24034153302413 is an apocalyptic number.
It is an amenable number.
4034153302413 is a deficient number, since it is larger than the sum of its proper divisors (1767513981363).
4034153302413 is a wasteful number, since it uses less digits than its factorization.
4034153302413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161373244.
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 4034153302413 its reverse (3142033514304), we get a palindrome (7176186816717).
The spelling of 4034153302413 in words is "four trillion, thirty-four billion, one hundred fifty-three million, three hundred two thousand, four hundred thirteen".
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