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403444442013 = 3134481480671
BaseRepresentation
bin1011101111011110010…
…10011010001110011101
31102120100201220011011020
411313233022122032131
523102223234121023
6505201222314353
741101505114004
oct5675712321635
91376321804136
10403444442013
11146110962698
12662348889b9
132c077124802
141575381bc3b
15a763ecdde3
hex5def29a39d

403444442013 has 4 divisors (see below), whose sum is σ = 537925922688. Its totient is φ = 268962961340.

The previous prime is 403444441937. The next prime is 403444442021. The reversal of 403444442013 is 310244444304.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 403444442013 - 218 = 403444179869 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (403444442083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67240740333 + ... + 67240740338.

It is an arithmetic number, because the mean of its divisors is an integer number (134481480672).

Almost surely, 2403444442013 is an apocalyptic number.

It is an amenable number.

403444442013 is a deficient number, since it is larger than the sum of its proper divisors (134481480675).

403444442013 is a wasteful number, since it uses less digits than its factorization.

403444442013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134481480674.

The product of its (nonzero) digits is 73728, while the sum is 33.

Adding to 403444442013 its reverse (310244444304), we get a palindrome (713688886317).

The spelling of 403444442013 in words is "four hundred three billion, four hundred forty-four million, four hundred forty-two thousand, thirteen".

Divisors: 1 3 134481480671 403444442013