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4040113131 = 32448901459
BaseRepresentation
bin1111000011001111…
…0011101111101011
3101102120012000022200
43300303303233223
531233232110011
61504521351243
7202055252325
oct36063635753
911376160280
104040113131
1117935a187a
12949038523
134c50278b2
142a47d6615
15189a4a856
hexf0cf3beb

4040113131 has 6 divisors (see below), whose sum is σ = 5835718980. Its totient is φ = 2693408748.

The previous prime is 4040113111. The next prime is 4040113141. The reversal of 4040113131 is 1313110404.

It is not a de Polignac number, because 4040113131 - 29 = 4040112619 is a prime.

It is a super-2 number, since 2×40401131312 = 32645028222557246322, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (4040113111) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 224450721 + ... + 224450738.

It is an arithmetic number, because the mean of its divisors is an integer number (972619830).

Almost surely, 24040113131 is an apocalyptic number.

4040113131 is a deficient number, since it is larger than the sum of its proper divisors (1795605849).

4040113131 is a wasteful number, since it uses less digits than its factorization.

4040113131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 448901465 (or 448901462 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

The square root of 4040113131 is about 63561.8842625044. The cubic root of 4040113131 is about 1592.6897146298.

Adding to 4040113131 its reverse (1313110404), we get a palindrome (5353223535).

The spelling of 4040113131 in words is "four billion, forty million, one hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 3 9 448901459 1346704377 4040113131