Search a number
-
+
4040113141 is a prime number
BaseRepresentation
bin1111000011001111…
…0011101111110101
3101102120012000100001
43300303303233311
531233232110031
61504521351301
7202055252341
oct36063635765
911376160301
104040113141
1117935a1889
12949038531
134c50278bc
142a47d6621
15189a4a861
hexf0cf3bf5

4040113141 has 2 divisors, whose sum is σ = 4040113142. Its totient is φ = 4040113140.

The previous prime is 4040113111. The next prime is 4040113159. The reversal of 4040113141 is 1413110404.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3995504100 + 44609041 = 63210^2 + 6679^2 .

It is a cyclic number.

It is not a de Polignac number, because 4040113141 - 217 = 4039982069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4040113111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2020056570 + 2020056571.

It is an arithmetic number, because the mean of its divisors is an integer number (2020056571).

Almost surely, 24040113141 is an apocalyptic number.

It is an amenable number.

4040113141 is a deficient number, since it is larger than the sum of its proper divisors (1).

4040113141 is an equidigital number, since it uses as much as digits as its factorization.

4040113141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

The square root of 4040113141 is about 63561.8843411679. The cubic root of 4040113141 is about 1592.6897159439.

Adding to 4040113141 its reverse (1413110404), we get a palindrome (5453223545).

The spelling of 4040113141 in words is "four billion, forty million, one hundred thirteen thousand, one hundred forty-one".