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40401134044413 = 313467044681471
BaseRepresentation
bin10010010111110100111110…
…01111100100010011111101
312022001022101111101210210020
421023322133033210103331
520243413010303410123
6221532005203002353
711336612523132462
oct1113723717442375
9168038344353706
1040401134044413
111196702aa0485a
1246460160693b9
131970a6cb465ac
149d95d511d669
154a0dd5e737e3
hex24be9f3e44fd

40401134044413 has 4 divisors (see below), whose sum is σ = 53868178725888. Its totient is φ = 26934089362940.

The previous prime is 40401134044409. The next prime is 40401134044423. The reversal of 40401134044413 is 31444043110404.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40401134044413 - 22 = 40401134044409 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40401134044423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6733522340733 + ... + 6733522340738.

It is an arithmetic number, because the mean of its divisors is an integer number (13467044681472).

Almost surely, 240401134044413 is an apocalyptic number.

It is an amenable number.

40401134044413 is a deficient number, since it is larger than the sum of its proper divisors (13467044681475).

40401134044413 is a wasteful number, since it uses less digits than its factorization.

40401134044413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13467044681474.

The product of its (nonzero) digits is 36864, while the sum is 33.

Adding to 40401134044413 its reverse (31444043110404), we get a palindrome (71845177154817).

The spelling of 40401134044413 in words is "forty trillion, four hundred one billion, one hundred thirty-four million, forty-four thousand, four hundred thirteen".

Divisors: 1 3 13467044681471 40401134044413