404013101141131 has 8 divisors (see below), whose sum is σ = 404280582742400. Its totient is φ = 403745631859008.

The previous prime is 404013101141099. The next prime is 404013101141141. The reversal of 404013101141131 is 131141101310404.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 404013101141131 - 2⁵ = 404013101141099 is a prime.

It is a super-2 number, since 2×404013101141131² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 404013101141096 and 404013101141105.

It is not an unprimeable number, because it can be changed into a prime (404013101141141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 63002095 + ... + 69117943.

It is an arithmetic number, because the mean of its divisors is an integer number (50535072842800).

Almost surely, 2^{404013101141131} is an apocalyptic number.

404013101141131 is a deficient number, since it is larger than the sum of its proper divisors (267481601269).

404013101141131 is a wasteful number, since it uses less digits than its factorization.

404013101141131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6159573.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 404013101141131 its reverse (131141101310404), we get a palindrome (535154202451535).

The spelling of 404013101141131 in words is "four hundred four trillion, thirteen billion, one hundred one million, one hundred forty-one thousand, one hundred thirty-one".