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4040143202111 = 19146121101651
BaseRepresentation
bin111010110010101011010…
…011001110011100111111
3112022020022112012122210112
4322302223103032130333
51012143203124431421
612332003254100235
7564614341411562
oct72625323163477
915266275178715
104040143202111
111318462569565
1255300b94a67b
13233ca3739973
14dd7889464d9
157016032c45b
hex3acab4ce73f

4040143202111 has 4 divisors (see below), whose sum is σ = 4040164495224. Its totient is φ = 4040121909000.

The previous prime is 4040143202107. The next prime is 4040143202237. The reversal of 4040143202111 is 1112023410404.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4040143202111 - 22 = 4040143202107 is a prime.

It is a super-3 number, since 3×40401432021113 (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4040143202411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10359365 + ... + 10742286.

It is an arithmetic number, because the mean of its divisors is an integer number (1010041123806).

Almost surely, 24040143202111 is an apocalyptic number.

4040143202111 is a deficient number, since it is larger than the sum of its proper divisors (21293113).

4040143202111 is a wasteful number, since it uses less digits than its factorization.

4040143202111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21293112.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 4040143202111 its reverse (1112023410404), we get a palindrome (5152166612515).

The spelling of 4040143202111 in words is "four trillion, forty billion, one hundred forty-three million, two hundred two thousand, one hundred eleven".

Divisors: 1 191461 21101651 4040143202111