Base | Representation |
---|---|
bin | 10010010111111101000000… |
… | …01100100110010001000111 |
3 | 12022001201111221020120111222 |
4 | 21023332200030212101013 |
5 | 20244000322410314003 |
6 | 221534001041550555 |
7 | 11340124410550646 |
oct | 1113764014462107 |
9 | 168051457216458 |
10 | 40405445010503 |
11 | 11968942382451 |
12 | 4646a1994545b |
13 | 19712a90052c1 |
14 | 9d98c389d35d |
15 | 4a1089671c38 |
hex | 24bfa0326447 |
40405445010503 has 4 divisors (see below), whose sum is σ = 40405710570720. Its totient is φ = 40405179450288.
The previous prime is 40405445010493. The next prime is 40405445010577. The reversal of 40405445010503 is 30501054450404.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40405445010503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40405445012503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132551750 + ... + 132856227.
It is an arithmetic number, because the mean of its divisors is an integer number (10101427642680).
Almost surely, 240405445010503 is an apocalyptic number.
40405445010503 is a deficient number, since it is larger than the sum of its proper divisors (265560217).
40405445010503 is a wasteful number, since it uses less digits than its factorization.
40405445010503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 265560216.
The product of its (nonzero) digits is 96000, while the sum is 35.
Adding to 40405445010503 its reverse (30501054450404), we get a palindrome (70906499460907).
The spelling of 40405445010503 in words is "forty trillion, four hundred five billion, four hundred forty-five million, ten thousand, five hundred three".
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