4041135113 has 4 divisors (see below), whose sum is σ = 4041266580. Its totient is φ = 4041003648.

The previous prime is 4041135097. The next prime is 4041135211. The reversal of 4041135113 is 3115311404.

It is a happy number.

4041135113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 504811024 + 3536324089 = 22468^2 + 59467^2 .

It is a cyclic number.

It is not a de Polignac number, because 4041135113 - 2⁴ = 4041135097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4041135013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7781 + ... + 90237.

It is an arithmetic number, because the mean of its divisors is an integer number (1010316645).

Almost surely, 2^4041135113 is an apocalyptic number.

It is an amenable number.

4041135113 is a deficient number, since it is larger than the sum of its proper divisors (131467).

4041135113 is an equidigital number, since it uses as much as digits as its factorization.

4041135113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131466.

The product of its (nonzero) digits is 720, while the sum is 23.

The square root of 4041135113 is about 63569.9230218191. The cubic root of 4041135113 is about 1592.8239982451.

Adding to 4041135113 its reverse (3115311404), we get a palindrome (7156446517).

The spelling of 4041135113 in words is "four billion, forty-one million, one hundred thirty-five thousand, one hundred thirteen".