Base | Representation |
---|---|
bin | 111010110100011010101… |
… | …100101010101000110101 |
3 | 112022102010202221122112100 |
4 | 322310122230222220311 |
5 | 1012211020102022013 |
6 | 12332512540012313 |
7 | 565011554216400 |
oct | 72643254525065 |
9 | 15272122848470 |
10 | 4042012142133 |
11 | 131923152a899 |
12 | 553451831099 |
13 | 2342109b6c34 |
14 | dd8c4c46d37 |
15 | 7021e452473 |
hex | 3ad1ab2aa35 |
4042012142133 has 108 divisors (see below), whose sum is σ = 6986333783520. Its totient is φ = 2245322286144.
The previous prime is 4042012142107. The next prime is 4042012142137. The reversal of 4042012142133 is 3312412102404.
4042012142133 is a `hidden beast` number, since 4 + 0 + 4 + 201 + 2 + 1 + 421 + 33 = 666.
It is not a de Polignac number, because 4042012142133 - 213 = 4042012133941 is a prime.
It is a super-3 number, since 3×40420121421333 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4042012142097 and 4042012142106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4042012142137) by changing a digit.
It is a polite number, since it can be written in 107 ways as a sum of consecutive naturals, for example, 931551678 + ... + 931556016.
Almost surely, 24042012142133 is an apocalyptic number.
It is an amenable number.
4042012142133 is a deficient number, since it is larger than the sum of its proper divisors (2944321641387).
4042012142133 is a wasteful number, since it uses less digits than its factorization.
4042012142133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5976 (or 5929 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 4042012142133 its reverse (3312412102404), we get a palindrome (7354424244537).
The spelling of 4042012142133 in words is "four trillion, forty-two billion, twelve million, one hundred forty-two thousand, one hundred thirty-three".
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