4042112024131 has 4 divisors (see below), whose sum is σ = 4093277999200. Its totient is φ = 3990946049064.

The previous prime is 4042112024089. The next prime is 4042112024177. The reversal of 4042112024131 is 1314202112404.

4042112024131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4042112024131 - 2¹¹ = 4042112022083 is a prime.

It is a super-2 number, since 2×4042112024131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4042112024096 and 4042112024105.

It is not an unprimeable number, because it can be changed into a prime (4042112004131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25582987416 + ... + 25582987573.

It is an arithmetic number, because the mean of its divisors is an integer number (1023319499800).

Almost surely, 2^{4042112024131} is an apocalyptic number.

4042112024131 is a deficient number, since it is larger than the sum of its proper divisors (51165975069).

4042112024131 is an equidigital number, since it uses as much as digits as its factorization.

4042112024131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51165975068.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 4042112024131 its reverse (1314202112404), we get a palindrome (5356314136535).

The spelling of 4042112024131 in words is "four trillion, forty-two billion, one hundred twelve million, twenty-four thousand, one hundred thirty-one".