Base | Representation |
---|---|
bin | 111010110101011100010… |
… | …101010010110001101101 |
3 | 112022111222111222211201002 |
4 | 322311130111102301231 |
5 | 1012220244001430331 |
6 | 12333214113530045 |
7 | 565051055052266 |
oct | 72653425226155 |
9 | 15274874884632 |
10 | 4043113311341 |
11 | 1319747073595 |
12 | 5536ba573925 |
13 | 234357b86b50 |
14 | dd98b1ab96d |
15 | 70285e699cb |
hex | 3ad5c552c6d |
4043113311341 has 16 divisors (see below), whose sum is σ = 4587128495040. Its totient is φ = 3532714093440.
The previous prime is 4043113311329. The next prime is 4043113311359. The reversal of 4043113311341 is 1431133113404.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4043113311341 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4043113319341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6565715 + ... + 7155056.
It is an arithmetic number, because the mean of its divisors is an integer number (286695530940).
Almost surely, 24043113311341 is an apocalyptic number.
It is an amenable number.
4043113311341 is a deficient number, since it is larger than the sum of its proper divisors (544015183699).
4043113311341 is a wasteful number, since it uses less digits than its factorization.
4043113311341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13721996.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 4043113311341 its reverse (1431133113404), we get a palindrome (5474246424745).
The spelling of 4043113311341 in words is "four trillion, forty-three billion, one hundred thirteen million, three hundred eleven thousand, three hundred forty-one".
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