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4043134113 = 31347711371
BaseRepresentation
bin1111000011111101…
…0101010010100001
3101102202212111022220
43300333111102201
531240020242423
61505110221253
7202123034004
oct36077252241
911382774286
104043134113
111795275557
1294a054829
134c5844965
142a4d8153b
15189e459e3
hexf0fd54a1

4043134113 has 4 divisors (see below), whose sum is σ = 5390845488. Its totient is φ = 2695422740.

The previous prime is 4043134091. The next prime is 4043134133. The reversal of 4043134113 is 3114313404.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4043134113 - 210 = 4043133089 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4043134133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 673855683 + ... + 673855688.

It is an arithmetic number, because the mean of its divisors is an integer number (1347711372).

Almost surely, 24043134113 is an apocalyptic number.

It is an amenable number.

4043134113 is a deficient number, since it is larger than the sum of its proper divisors (1347711375).

4043134113 is a wasteful number, since it uses less digits than its factorization.

4043134113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1347711374.

The product of its (nonzero) digits is 1728, while the sum is 24.

The square root of 4043134113 is about 63585.6439221936. The cubic root of 4043134113 is about 1593.0865919815.

Adding to 4043134113 its reverse (3114313404), we get a palindrome (7157447517).

The spelling of 4043134113 in words is "four billion, forty-three million, one hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 3 1347711371 4043134113