4043213313133 has 4 divisors (see below), whose sum is σ = 4043221397820. Its totient is φ = 4043205228448.

The previous prime is 4043213313119. The next prime is 4043213313143. The reversal of 4043213313133 is 3313133123404.

4043213313133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 304392751524 + 3738820561609 = 551718^2 + 1933603^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4043213313133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4043213313095 and 4043213313104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4043213313103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3238960 + ... + 4310137.

It is an arithmetic number, because the mean of its divisors is an integer number (1010805349455).

Almost surely, 2^{4043213313133} is an apocalyptic number.

It is an amenable number.

4043213313133 is a deficient number, since it is larger than the sum of its proper divisors (8084687).

4043213313133 is an equidigital number, since it uses as much as digits as its factorization.

4043213313133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8084686.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 4043213313133 its reverse (3313133123404), we get a palindrome (7356346436537).

The spelling of 4043213313133 in words is "four trillion, forty-three billion, two hundred thirteen million, three hundred thirteen thousand, one hundred thirty-three".