Base | Representation |
---|---|
bin | 111010110110011001100… |
… | …110110101110000100011 |
3 | 112022121122011101011012012 |
4 | 322312121212311300203 |
5 | 1012224400134240001 |
6 | 12333504115423135 |
7 | 565115410022603 |
oct | 72663146656043 |
9 | 15277564334165 |
10 | 4044141321251 |
11 | 131a124388659 |
12 | 5539468b4aab |
13 | 23448cb50235 |
14 | dda4792ac03 |
15 | 702e63302bb |
hex | 3ad999b5c23 |
4044141321251 has 4 divisors (see below), whose sum is σ = 4044399765000. Its totient is φ = 4043882877504.
The previous prime is 4044141321239. The next prime is 4044141321299. The reversal of 4044141321251 is 1521231414404.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4044141321251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4044141321221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129198401 + ... + 129229698.
It is an arithmetic number, because the mean of its divisors is an integer number (1011099941250).
Almost surely, 24044141321251 is an apocalyptic number.
4044141321251 is a deficient number, since it is larger than the sum of its proper divisors (258443749).
4044141321251 is a wasteful number, since it uses less digits than its factorization.
4044141321251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 258443748.
The product of its (nonzero) digits is 15360, while the sum is 32.
Adding to 4044141321251 its reverse (1521231414404), we get a palindrome (5565372735655).
The spelling of 4044141321251 in words is "four trillion, forty-four billion, one hundred forty-one million, three hundred twenty-one thousand, two hundred fifty-one".
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