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40450353551 = 175392306309
BaseRepresentation
bin100101101011000001…
…110110100110001111
310212102001110212102122
4211223001312212033
51130320242303201
630325503243155
72631253221626
oct455301664617
9125361425378
1040450353551
1116178196363
127a0a8a94bb
133a7847415a
141d5a31c6bd
1510bb2e4e1b
hex96b07698f

40450353551 has 4 divisors (see below), whose sum is σ = 40452677400. Its totient is φ = 40448029704.

The previous prime is 40450353547. The next prime is 40450353553. The reversal of 40450353551 is 15535305404.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40450353551 - 22 = 40450353547 is a prime.

It is a super-2 number, since 2×404503535512 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40450353553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1135616 + ... + 1170693.

It is an arithmetic number, because the mean of its divisors is an integer number (10113169350).

Almost surely, 240450353551 is an apocalyptic number.

40450353551 is a deficient number, since it is larger than the sum of its proper divisors (2323849).

40450353551 is a wasteful number, since it uses less digits than its factorization.

40450353551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2323848.

The product of its (nonzero) digits is 90000, while the sum is 35.

Adding to 40450353551 its reverse (15535305404), we get a palindrome (55985658955).

The spelling of 40450353551 in words is "forty billion, four hundred fifty million, three hundred fifty-three thousand, five hundred fifty-one".

Divisors: 1 17539 2306309 40450353551