404552043413141 has 4 divisors (see below), whose sum is σ = 435671431368012. Its totient is φ = 373432655458272.

The previous prime is 404552043413107. The next prime is 404552043413149. The reversal of 404552043413141 is 141314340255404.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 47783071000900 + 356768972412241 = 6912530^2 + 18888329^2 .

It is a cyclic number.

It is not a de Polignac number, because 404552043413141 - 2¹⁰ = 404552043412117 is a prime.

It is a super-2 number, since 2×404552043413141² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (404552043413149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15559693977416 + ... + 15559693977441.

It is an arithmetic number, because the mean of its divisors is an integer number (108917857842003).

Almost surely, 2^{404552043413141} is an apocalyptic number.

It is an amenable number.

404552043413141 is a deficient number, since it is larger than the sum of its proper divisors (31119387954871).

404552043413141 is a wasteful number, since it uses less digits than its factorization.

404552043413141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31119387954870.

The product of its (nonzero) digits is 460800, while the sum is 41.

Adding to 404552043413141 its reverse (141314340255404), we get a palindrome (545866383668545).

The spelling of 404552043413141 in words is "four hundred four trillion, five hundred fifty-two billion, forty-three million, four hundred thirteen thousand, one hundred forty-one".