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40500112253 = 130730987079
BaseRepresentation
bin100101101101111111…
…101010101101111101
310212112112002212112112
4211231333222231331
51130421012043003
630334441543405
72632426163006
oct455577525575
9125475085475
1040500112253
11161a3291857
127a234a4b65
133a85876783
141d62b921ad
1510c08733d8
hex96dfeab7d

40500112253 has 4 divisors (see below), whose sum is σ = 40531100640. Its totient is φ = 40469123868.

The previous prime is 40500112217. The next prime is 40500112291. The reversal of 40500112253 is 35221100504.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40500112253 - 28 = 40500111997 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40500112753) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15492233 + ... + 15494846.

It is an arithmetic number, because the mean of its divisors is an integer number (10132775160).

Almost surely, 240500112253 is an apocalyptic number.

It is an amenable number.

40500112253 is a deficient number, since it is larger than the sum of its proper divisors (30988387).

40500112253 is a wasteful number, since it uses less digits than its factorization.

40500112253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30988386.

The product of its (nonzero) digits is 1200, while the sum is 23.

Adding to 40500112253 its reverse (35221100504), we get a palindrome (75721212757).

The spelling of 40500112253 in words is "forty billion, five hundred million, one hundred twelve thousand, two hundred fifty-three".

Divisors: 1 1307 30987079 40500112253