Base | Representation |
---|---|
bin | 10010011010101101100001… |
… | …11110001101010011010011 |
3 | 12022101210010200002000102021 |
4 | 21031112300332031103103 |
5 | 20302023420211401121 |
6 | 222045313043232311 |
7 | 11350021046440552 |
oct | 1115266076152323 |
9 | 168353120060367 |
10 | 40500215731411 |
11 | 119a5054a3a797 |
12 | 4661268378697 |
13 | 197a20031a057 |
14 | a00314217d99 |
15 | 4a3784765641 |
hex | 24d5b0f8d4d3 |
40500215731411 has 8 divisors (see below), whose sum is σ = 41973234766848. Its totient is φ = 39037606725000.
The previous prime is 40500215731399. The next prime is 40500215731447. The reversal of 40500215731411 is 11413751200504.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 40500215731411 - 215 = 40500215698643 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (40500215731211) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2602499335 + ... + 2602514896.
It is an arithmetic number, because the mean of its divisors is an integer number (5246654345856).
Almost surely, 240500215731411 is an apocalyptic number.
40500215731411 is a deficient number, since it is larger than the sum of its proper divisors (1473019035437).
40500215731411 is a wasteful number, since it uses less digits than its factorization.
40500215731411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5205014513.
The product of its (nonzero) digits is 16800, while the sum is 34.
Adding to 40500215731411 its reverse (11413751200504), we get a palindrome (51913966931915).
The spelling of 40500215731411 in words is "forty trillion, five hundred billion, two hundred fifteen million, seven hundred thirty-one thousand, four hundred eleven".
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