Search a number
-
+
405254371313 = 1136841306483
BaseRepresentation
bin1011110010110110000…
…10101111011111110001
31102202000212121002101202
411321123002233133301
523114430104340223
6510100555340545
741164403214551
oct5713302573761
91382025532352
10405254371313
1114695a589330
126665aa51755
132c2a50b01ac
1415885d5b161
15a81cd49428
hex5e5b0af7f1

405254371313 has 4 divisors (see below), whose sum is σ = 442095677808. Its totient is φ = 368413064820.

The previous prime is 405254371271. The next prime is 405254371399. The reversal of 405254371313 is 313173452504.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 405254371313 - 226 = 405187262449 is a prime.

It is a super-2 number, since 2×4052543713132 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (405254371213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18420653231 + ... + 18420653252.

It is an arithmetic number, because the mean of its divisors is an integer number (110523919452).

Almost surely, 2405254371313 is an apocalyptic number.

It is an amenable number.

405254371313 is a deficient number, since it is larger than the sum of its proper divisors (36841306495).

405254371313 is a wasteful number, since it uses less digits than its factorization.

405254371313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36841306494.

The product of its (nonzero) digits is 151200, while the sum is 38.

The spelling of 405254371313 in words is "four hundred five billion, two hundred fifty-four million, three hundred seventy-one thousand, three hundred thirteen".

Divisors: 1 11 36841306483 405254371313