Base | Representation |
---|---|
bin | 10010011011100101110101… |
… | …00011010101011101001001 |
3 | 12022111200011010200102220122 |
4 | 21031302322203111131021 |
5 | 20303022320423331103 |
6 | 222111232212433025 |
7 | 11352141055104260 |
oct | 1115627243253511 |
9 | 168450133612818 |
10 | 40530441230153 |
11 | 11a069554a2316 |
12 | 46670a2918775 |
13 | 1980009326654 |
14 | a019805a15d7 |
15 | 4a4453083b38 |
hex | 24dcba8d5749 |
40530441230153 has 32 divisors (see below), whose sum is σ = 47115409256448. Its totient is φ = 34146507225600.
The previous prime is 40530441230113. The next prime is 40530441230159. The reversal of 40530441230153 is 35103214403504.
It is not a de Polignac number, because 40530441230153 - 230 = 40529367488329 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (40530441230159) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1963578713 + ... + 1963599353.
It is an arithmetic number, because the mean of its divisors is an integer number (1472356539264).
Almost surely, 240530441230153 is an apocalyptic number.
It is an amenable number.
40530441230153 is a deficient number, since it is larger than the sum of its proper divisors (6584968026295).
40530441230153 is a wasteful number, since it uses less digits than its factorization.
40530441230153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29733.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 40530441230153 its reverse (35103214403504), we get a palindrome (75633655633657).
The spelling of 40530441230153 in words is "forty trillion, five hundred thirty billion, four hundred forty-one million, two hundred thirty thousand, one hundred fifty-three".
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