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40552541135 = 5487106315667
BaseRepresentation
bin100101110001000111…
…101010101111001111
310212200011202112102222
4211301013222233033
51131022422304020
630343553405555
72633633624621
oct456107525717
9125604675388
1040552541135
111621a941407
127a38b698bb
133a936a2592
141d69b1cc11
1510c527cb25
hex9711eabcf

40552541135 has 16 divisors (see below), whose sum is σ = 48811961856. Its totient is φ = 32342895648.

The previous prime is 40552541131. The next prime is 40552541137. The reversal of 40552541135 is 53114525504.

It is a cyclic number.

It is not a de Polignac number, because 40552541135 - 22 = 40552541131 is a prime.

It is a super-3 number, since 3×405525411353 (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 40552541095 and 40552541104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40552541131) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2580572 + ... + 2596238.

It is an arithmetic number, because the mean of its divisors is an integer number (3050747616).

Almost surely, 240552541135 is an apocalyptic number.

40552541135 is a deficient number, since it is larger than the sum of its proper divisors (8259420721).

40552541135 is a wasteful number, since it uses less digits than its factorization.

40552541135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17222.

The product of its (nonzero) digits is 60000, while the sum is 35.

The spelling of 40552541135 in words is "forty billion, five hundred fifty-two million, five hundred forty-one thousand, one hundred thirty-five".

Divisors: 1 5 487 1063 2435 5315 15667 78335 517681 2588405 7629829 16654021 38149145 83270105 8110508227 40552541135