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405551942493 = 3135183980831
BaseRepresentation
bin1011110011011001100…
…01111000101101011101
31102202210121112021022120
411321230301320231131
523121032244124433
6510150305333153
741204645430165
oct5715461705535
91382717467276
10405551942493
11146aa2553a25
12667226371b9
132c32193a609
14158b369b5a5
15a8390287b3
hex5e6cc78b5d

405551942493 has 4 divisors (see below), whose sum is σ = 540735923328. Its totient is φ = 270367961660.

The previous prime is 405551942447. The next prime is 405551942533. The reversal of 405551942493 is 394249155504.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 405551942493 - 26 = 405551942429 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (405551942443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67591990413 + ... + 67591990418.

It is an arithmetic number, because the mean of its divisors is an integer number (135183980832).

Almost surely, 2405551942493 is an apocalyptic number.

It is an amenable number.

405551942493 is a deficient number, since it is larger than the sum of its proper divisors (135183980835).

405551942493 is a wasteful number, since it uses less digits than its factorization.

405551942493 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 135183980834.

The product of its (nonzero) digits is 3888000, while the sum is 51.

The spelling of 405551942493 in words is "four hundred five billion, five hundred fifty-one million, nine hundred forty-two thousand, four hundred ninety-three".

Divisors: 1 3 135183980831 405551942493