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406331388881 = 1136939217171
BaseRepresentation
bin1011110100110110011…
…11001111001111010001
31102211210221012020202022
411322123033033033101
523124131313421011
6510355511501225
741233161550505
oct5723317171721
91384727166668
10406331388881
111473625265a0
12668bb687815
132c4172750b2
1415948dd6305
15a8826908db
hex5e9b3cf3d1

406331388881 has 4 divisors (see below), whose sum is σ = 443270606064. Its totient is φ = 369392171700.

The previous prime is 406331388877. The next prime is 406331388943. The reversal of 406331388881 is 188883133604.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 406331388881 - 22 = 406331388877 is a prime.

It is a super-2 number, since 2×4063313888812 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (406331384881) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18469608575 + ... + 18469608596.

It is an arithmetic number, because the mean of its divisors is an integer number (110817651516).

Almost surely, 2406331388881 is an apocalyptic number.

It is an amenable number.

406331388881 is a deficient number, since it is larger than the sum of its proper divisors (36939217183).

406331388881 is a wasteful number, since it uses less digits than its factorization.

406331388881 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36939217182.

The product of its (nonzero) digits is 2654208, while the sum is 53.

The spelling of 406331388881 in words is "four hundred six billion, three hundred thirty-one million, three hundred eighty-eight thousand, eight hundred eighty-one".

Divisors: 1 11 36939217171 406331388881