4100221154133 has 12 divisors (see below), whose sum is σ = 6378121795500. Its totient is φ = 2523213017856.

The previous prime is 4100221154111. The next prime is 4100221154171. The reversal of 4100221154133 is 3314511220014.

4100221154133 is a `hidden beast` number, since 4 + 10 + 0 + 221 + 15 + 413 + 3 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 2231865687249 + 1868355466884 = 1493943^2 + 1366878^2 .

It is not a de Polignac number, because 4100221154133 - 2⁶ = 4100221154069 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4100221154097 and 4100221154106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4100221152133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 17522312508 + ... + 17522312741.

It is an arithmetic number, because the mean of its divisors is an integer number (531510149625).

Almost surely, 2^{4100221154133} is an apocalyptic number.

It is an amenable number.

4100221154133 is a deficient number, since it is larger than the sum of its proper divisors (2277900641367).

4100221154133 is a wasteful number, since it uses less digits than its factorization.

4100221154133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35044625268 (or 35044625265 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 4100221154133 its reverse (3314511220014), we get a palindrome (7414732374147).

The spelling of 4100221154133 in words is "four trillion, one hundred billion, two hundred twenty-one million, one hundred fifty-four thousand, one hundred thirty-three".